Re: Array of string...

On 2006-12-27, Christen Fihl <look_at_HSPascal.fihl.net@nospam.plz>
wrote:
>
> correct:
> type parole=string;
> type vettore=array[5] of parole; max 5 strings in array
>

That won't compile either; I'd change it to

type 
   vettor = array[1..5] of parole; { 5 strings in the array}

On Wed, 27 Dec 2006 11:06:22 GMT, "Alberto"
<darsana85@libero.it>
wrote:

>How can i create an array of string ?
>I try to write this code but it isn't right:
>
>type parole=string;
>type vettore=array of parole;
>
>var v:vettore;
>    frase:parole;
>    i:integer;
>begin
> for i:=1 to 5 do
>  begin
>   writeln('Inserisci una frase, digita 0 per terminare: ');
>   readln(frase);
>    if (frase<>'0') then
>      v[i]:=frase;
>  end;
>
>
>end.

You have to set the length of a dynamic array before you do anything
with it.  They are always created at length zero.

How can i create an array of string ?
I try to write this code but it isn't right:

type parole=string;
type vettore=array of parole;

var v:vettore;
    frase:parole;
    i:integer;
begin
 for i:=1 to 5 do
  begin
   writeln('Inserisci una frase, digita 0 per terminare: ');
   readln(frase);
    if (frase<>'0') then
      v[i]:=frase;
  end;


end.

Alberto

You need to tell how big an array. (Else you need pointers)

you wrote:
type parole=string;
type vettore=array of parole;  no count

correct:
type parole=string;
type vettore=array[5] of parole; max 5 strings in array

Christen

Sure, my mistake.

Normally when programming, I let the fingers do the typing.
When answering mails outside of Turbo/Delphi, I let the brain with all 
its faults do the work ;-)

Christen